The sum of the ages of two children is 12 and their product is 32. The age of elder one is:
A. 2
B. 3
C. 4
D. 8
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The ratio of the ages of two friends A and B is 3:2. However, if the age of A is decreased by 10 and that of B is increased by 10 then the original ratio is reversed. Age of A is:
A. 20
B. 25
C. 30
D. 50
The average age of A and B is 20. If C were to replace A the average would be 19 and if B was replaced by C the average would be 21. The age of C is:
A. 18
B. 19
C. 20
D. 21
The sum of the present ages of A B and C is 90 years. 6 years ago their ages were in the ratio of 1:2:3. C’s present age is:
A. 24
B. 30
C. 32
D. 36
20 years ago my age was 1/3 of what it is now what is my present age?
A. 30
B. 33
C. 36
D. 66
Ten years ago Akram was thrice as old as Aslam was but 10 years hence he will be only twice as old. What is Akram’s present age?
A. 30
B. 50
C. 60
D. 70
Ten years ago a father was seven times as old as his son two years hence twice his age will be equal to five times his sons. What is the present age of son?
A. 14
B. 20
C. 6
D. 80
A father is 15 times older than his son. However 18 years later he will be only thrice as old as the son. What is the father’s present age?
A. 21
B. 25
C. 45
D. 60
Ages of A and B are in ration 8:7. 27 years ago their ages were in the ration 5:4. The age of B is:
A. 63
B. 65
C. 68
D. 72
The sum of the ages of a son and a father is 64. After 4 years the age of father will be three times that of his sons. The age of the father is:
A. 40
B. 50
C. 44
D. 45