The ages of X and Y are in the ratio 7:4. If the sum of their present ages is 55 then the age of X is:
A. 20
B. 25
C. 30
D. 35
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A mothers age after 5 years will be twice the age of her daughter. The difference of their ages is 19. What is the age of the mother?
A. 13
B. 33
C. 15
D. 12
C’s mother was four times as old as C ten years ago. After 10 years she will be twice as old as C is now. How old C is now?
A. 15
B. 30
C. 20
D. 25
Meena is thrice as old as Sheraz. Fatima will be twice as old as Meena 6 years hence. Six years ago Sheraz was five years old. What is Fatima’s present age?
A. 65
B. 70
C. 68
D. 72
The product of the ages of two class fellows is 24. If the greater fellow is 3/2 times the smaller one then the age of the smaller fellow is:
A. 8
B. 6
C. 4
D. 2
A sum of the present ages of a mother and daughter is 63. Three years back if the age of the mother was double that of the daughter then the present age of the daughter is:
A. 21 years
B. 24 years
C. 22 years
D. 15 years
A mans age is three times his sons. In 15 years it will be double that of his sons. How old is the son now?
A.30
B.15
C.45
D.none
When .36 is written in simplest fraction form, the sum of numerator and the denominator is –?
A. 10
B. 34
C. 20
D. 25
Which of the following fraction is the smallest?
A. 13/16
B. 15/19
C. 17/21
D. 7/8
12.1212 + 17.0005 – 9.1102 =?
A. 20.15
B. 20.0105
C. 20.0015
D. 20.0115