The average age in a city of 10000 is 40 years. The average of half of them is 50 years. The average of remaining ones is.

5 Comments to “The average age in a city of 10000 is 40 years. The average of half of them is 50 years. The average of remaining ones is.”

1. give the solution

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   1. Age of population in a city of 10,000 is 40 yr= 10,000 × 40 = 400,000

      Age of half of them mean = 10,000 ÷ 2 = 5,000

      Age of half of them is 50 years = 5,000 × 50 = 250,000
      Remaining age = 400,000 – 250,000 = 150,000

      The average of remaining ones is = 150,000 ÷ 5000 = 30

      Reply

   2. Age of population in a city of 10,000 is 40 yr= 10,000 × 40 = 400,000

      Age of half of them mean = 10,000 ÷ 2 = 5,000

      Age of half of them is 50 years = 5,000 × 50 = 250,000
      Remaining age = 400,000 – 250,000 = 150,000

      The average of remaining ones is = 150,000 ÷ 5000 = 30

      Reply

2. Step by step explanation plz. Thank you

   Reply

   1. Age of population in a city of 10,000 is 40 yr= 10,000 × 40 = 400,000

      Age of half of them mean = 10,000 ÷ 2 = 5,000

      Age of half of them is 50 years = 5,000 × 50 = 250,000
      Remaining age = 400,000 – 250,000 = 150,000

      The average of remaining ones is = 150,000 ÷ 5000 = 30

      Reply

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